In a radioactive sample, the fraction of initial number of redioactive nuclie, which remains undecayed after n mean lives is
A. `(1)/(e^(n))`
B. `e^(n)`
C. `1-(1)/(e^(n))`
D. `((1)/(e-1))^(n)`

4 views

1 Answers

Correct Answer - A
`(N)/(N_(0))=e^(-lamda((n)/(lamda)))=(1)/(e^(n))" "(therefore"mean life", t=(1)/(lamda))`

4 views

Related Questions