Two redioactive materials `X_(1)andX_(2)` have decay constants `10lamdaandlamda`, respecitvely. If initially they have the same number of nuclei, then
Two redioactive materials `X_(1)andX_(2)` have decay constants `10lamdaandlamda`, respecitvely. If initially they have the same number of nuclei, then the ratio of the number of nuclei of `X_(1)` to that of `X_(2)` will be 1/e after a time
A. `(1)/((10lamda))`
B. `((1)/(11lamda))`
C. `(11)/((10lamda))`
D. `(1)/((9lamda))`
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Correct Answer - D
We have, `1/e=(N_(0)e^(-10lamdat))/(N_(0)e^(-lamdat))=e^(9lamdat)ort=(1)/(9lamda)(given(N_(1))/(N_(2))=1/e)`
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