Common difference of an Arithmetic Progression, whose 3rd term is 5 and 7th term is 9, is 

A) 1 

B) 2 

C) 3 

D) 4

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1 Answers

Correct option is (A) 1

We have \(a_3=5\;\&\;a_7=9\)

\(\therefore a+2d=5\)   ______________(1)

\(a+6d=9\)   ______________(2)    \((\because a_n=a+(n-1)d)\)

Subtract equation (1) from (2), we get

\((a+6d)-(a+2d)=9-5\)

\(\Rightarrow4d=4\)

\(\Rightarrow d=\frac44=1\)

\(\therefore a=5-2d\)                (From (1))

\(=5-2=3\)

Hence, common difference of given arithmetic progression is d = 1.

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