What will be the value of x if 8x + 4 , 6x – 2 and 2x + 7 are in arithmetic progression?
What will be the value of x if 8x + 4 , 6x – 2 and 2x + 7 are in arithmetic progression?
A) -15/2
B) 15/2
C) 15
D) -15
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Correct option is (B) 15/2
Given that 8x+4, 6x – 2 and 2x+7 are in A.P.
\(\therefore2(6x-2)=8x+4+2x+7\) \((\because\) If a, b & c are in A.P. then 2b = a+c)
\(\Rightarrow12x-4=10x+11\)
\(\Rightarrow12x-10x=11+4=15\)
\(\Rightarrow2x=15\)
\(\Rightarrow\) x = \(\frac{15}{2}\)
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