A transition metal M can exist in two oxidation states +2 and +3 It forms an oxide whose experiments formula is given by `M_xO` where `xlt1` Then the

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A transition metal M can exist in two oxidation states +2 and +3 It forms an oxide whose experiments formula is given by `M_xO` where `xlt1` Then the

A transition metal M can exist in two oxidation states +2 and +3 It forms an oxide whose experiments formula is given by `M_xO` where `xlt1` Then the ratio of metal ions in +3 state to those in +2 states in oxide given by :
A. `(1-x)/(1+x)`
B. 1+2x
C. `1+x/2`
D. `(2(1-x))/(3x-2)`

Monjur Alahi

7 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
In 1 mole of `M_x O_1` mole of `M^(2+)` ion=y `:.` mole of `M^(3+)` ion =x-y
Applying charge balance, 2y+3(x-y)-2=0 `implies` y=3x-2
`:. M^(3+)/M^(2+)=(x-y)/y=(x-(3x-2))/(3x-2)=((-2x+2))/(3x-2)=(2(1-x))/(3x-2)`

7 views Answered 2023-02-05 15:29