In an ionic solid `r_((+)) = 1.6 Å and r_((-)) = 1.864 Å`. Use the radius ratio rule to determine the edge length of the cubic unit cell in `Å`

Question

In an ionic solid `r_((+)) = 1.6 Å and r_((-)) = 1.864 Å`. Use the radius ratio rule to determine the edge length of the cubic unit cell in `Å`

In an ionic solid `r_((+)) = 1.6 Å and r_((-)) = 1.864 Å`. Use the radius ratio rule to determine the edge length of the cubic unit cell in `Å`
A. 4
B. `2sqrt3`
C. `3sqrt3`
D. `4/sqrt3`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`r_+/r_(-) = 1.6/1.864=0.858`
So, It is CsCl type of unit cell
So `sqrt3 a=2(r_+ +r_-)`
So `a=(2(1.864+1.6))/sqrt3Å=2xx2Å=4Å`

4 views Answered 2023-02-05 15:29