The conductivity ofa solution may be taken to be directly proportional to the total concentration of the charge carriers (ions) present in it in many

Question

The conductivity ofa solution may be taken to be directly proportional to the total concentration of the charge carriers (ions) present in it in many

The conductivity ofa solution may be taken to be directly proportional to the total concentration of the charge carriers (ions) present in it in many cases. Using the above, find the percent decrease in conductivity (k) of a solution of a week monoacidic base BOH when its 0.1 M solution is diluted to double its original volume. `(K_(b) = 10^(-5) for BOH) (take `sqrt(50) = 7.07`) (mark the answer to nearest integer)

Monjur Alahi

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2025-01-04 04:42

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - 29
Initially `[OH^(-)]=sqrt(10^(-5)xx0.1)=10^(-3)`
`[ions]_("total")=2xx10^(-3) M`
later `[OH^(-)]=sqrt(10^(-5)xx1/20)=sqrt50xx10^(-4) M`
`[ions]_("total")=2sqrt50xx10^(-4) M`
`therefore` % change on `["ions"]_("total")=(2sqrt50-20)/20xx100=-29.29%`

5 views Answered 2023-02-05 15:29