A sparingly soluble salt MX is dissolved in water to prepare 1 L saturated solution.Now `10^(-6)` mole NaX (assume 100% dissociation ) is added into t
A sparingly soluble salt MX is dissolved in water to prepare 1 L saturated solution.Now `10^(-6)` mole NaX (assume 100% dissociation ) is added into this.Conductivity of this solution is `29xx10^(-6) S//m`.If `K_(sp)` of MX is `axx10^(-b)`,then find value of (a+b),a is a natural number & `1le a le 9`.
Given:`lambda_((x)^(-))^(0)=4xx10^(-3) S m^(2) mol^(-)`
`lambda_((Na)^(+))^(0)=5xx10^(-3) S m^(2) mol^(-)`
`lambda_((M)^(+))^(0)=6xx10^(-3) S m^(2) mol^(-)`
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Correct Answer - 18
`MX hArrM^++X^(-)`
`x " " x+10^(-6)`
`[Na^+]=10^(-6) M`
`K_("Sol")=K_(M^+)+K_(X^(-))+K_(Na^+)`
`29xx10^(-6) = 10^3 [6xx10x +(4xx10^(-3)(x+10^(-6))+(5xx10^(-3)xx10^(-6))]`
`x=2xx10^(-6)`
`K_(sp)=2xx10^(-6) xx3xx10^(-6)=6xx10^(-12)`
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