If the wavelength of the first member of Blmer series of hydrogen spectrum is 6563Å A, then the wavelength of second member of Blamer series will be

Question

If the wavelength of the first member of Blmer series of hydrogen spectrum is 6563Å A, then the wavelength of second member of Blamer series will be

If the wavelength of the first member of Blmer series of hydrogen spectrum is 6563Å A, then the wavelength of second member of Blamer series will be
A. 1215Å
B. 4861Å
C. 6050Å
D. data given is insufficient to calculate the value

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`lambdaprop(1)/(((1)/(n_(f)^(2))-(1)/(n_(i)^(2))))`
`:." " (lambda)/(6563)=((1//4-1//9))/((1//4-1//16))=((5//36))/((12//64))`
`:. " " lambda=4861Å`

5 views Answered 2023-02-05 15:29