Radii of curvature of a canverging lends are in the ration 1:2. Its focal length is 6cm and refractive index is 1:5. Then, its radii of curvature are…

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Radii of curvature of a canverging lends are in the ration 1:2. Its focal length is 6cm and refractive index is 1:5. Then, its radii of curvature are…

Radii of curvature of a canverging lends are in the ration 1:2. Its focal length is 6cm and refractive index is 1:5. Then, its radii of curvature are…
A. 9cm and 18cm
B. 6cm and 12cm
C. 3cm and 6cm
D. 4.5cm and 9cm

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Given `(R_(1))/(R_(2))=(1)/(2),f=6`cm and `mu=1.5`
Let, `R_(1)=R and R_(2)=2R`
We know that the focal length of converging lens by using releationg , `(1)/(f)=(mu-1)[(1)/(R_(1))-(1)/(R_(2))]`
Substituting all the values, we get
`R=4.5cm`
`R_(1)=4.5cm`
and `R_(2)=2xx4.5=9cm`

5 views Answered 2023-02-05 15:29