If `mu_(v)=1.530 and mu_(R)=1.5145`, then disperisve power of a crown glass is
If `mu_(v)=1.530 and mu_(R)=1.5145`, then disperisve power of a crown glass is
A. 0.0164
B. 0.00701
C. 0.0132
D. 0.032
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Correct Answer - A
Here, `mu_(V)=1.5230 and mu_(R)=1.5145`
Therefore, means refractive index.
`mu=(1.523+1.5145)/(2)=1.5187`
Now, disperisive power, `omega` is given by
`omega=(mu_(V)-mu_(R))/(mu-1)=(1.5230-1.5145)/(1.51787-1)=0.0164`
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