A glass-slab is immersed in water. What will be the crirtical angle for a light ray at glass-water interface? Where `_(a)n_(g)=1.50,_(a)n_(w)=1.33 and sin^(-1)(0.887)=62.5`
A. `48.8^(@)`
B. `72.8^(@)`
C. `62.5^(@)`
D. `64.5^(@)`

5 views

1 Answers

Correct Answer - C
(c ) The refractive index of glass relative to water is given by,
`""_(w)n_(g)=(""_(a)n_(g))/(""_(a)n_(w))=1.50/1.33`
If C be the crirical angle at glass water interface, then
`Sin C=(1)/(""_(w)n_(g))=1.33/1.50=0.8867`
`C=sin_(.)^(-1)(0.8867)=62.5`

5 views

Related Questions