A ray of light is incident at an angle of `60^(@)` on one face of a prism of angle `30^(@)`. The ray emerging out of the prism makes an angle of `30^(

Question

A ray of light is incident at an angle of `60^(@)` on one face of a prism of angle `30^(@)`. The ray emerging out of the prism makes an angle of `30^(

A ray of light is incident at an angle of `60^(@)` on one face of a prism of angle `30^(@)`. The ray emerging out of the prism makes an angle of `30^(@)` with the incident ray. The emergent ray is
A. normal to the face through which it emerges
B. Incline at `30^(@)` to the face through it emerges
C. inclined at `60^(@)` to the face through it emerges
D. None of these

Monjur Alahi

7 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
(a) Deviation of ray in prism is given by,
`delta=i+e-A`
So, `e=delta+A-i=30^(@)-60^(@)=0^(@)`
So, emergent ray will be perpendicular to face, or emergent ray will make an angle of `90^(@)` with the face through which it emerges.

7 views Answered 2023-02-05 15:29