A double convex thin lens made of glass (refractive index `mu = 1.5`) has both radii of curvature of magnitude 20 cm . Incident light rays parallel to

Question

A double convex thin lens made of glass (refractive index `mu = 1.5`) has both radii of curvature of magnitude 20 cm . Incident light rays parallel to

A double convex thin lens made of glass (refractive index `mu = 1.5`) has both radii of curvature of magnitude 20 cm . Incident light rays parallel to the axis of the lens will converge at a distance L such that
A. L=20 cm
B. L=10 cm
C. L=40 cm
D. L=`20/3`cm

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

Refractive index of glass with respect to water is (9/8). Refractive index of glass with respect to air is (3/2). Find the refractive index of water w

2 Answers 7 Views

If in a plano-convex lens, the radius of curvature of the convex surface is 10 cm and the focal length of the lens is 30 cm , then the refractive inde

2 Answers 5 Views

The radii of curvature of the two surfaces of a lens are 20 cm and 30 cm and the refractive index of the material of the lens is 1.5. If the lens is c

2 Answers 5 Views

A plano-concave lens is made of glass of refractive index 1.5 and the radius of curvature of its curved face is 100 cm. What is the power of the lens?

2 Answers 8 Views

A thin prism P with angle `4^(@)` and made from glass of refractive index 1.54 is combined with another thin prism P made from glass of refractive ind

2 Answers 5 Views

Radii of curvature of a canverging lends are in the ration 1:2. Its focal length is 6cm and refractive index is 1:5. Then, its radii of curvature are…

2 Answers 5 Views

The radius of curvature of the convex face of a plano convex lens is 12cm and the refractive index of the material of the lends 1.5. Then, the focal l

2 Answers 5 Views

Two symmetric double convex lenses A and B have same focal length but the radii of curvature differ so that `R_(A) = 0.9R_(B)`. If refractive index of

2 Answers 5 Views

A lens behaves as a converging lens in air and a diverging lens in water. The refractive index of the material is (refractive index of water `=1.33`)

2 Answers 5 Views

A biconcave lens made of transparent material of refractive index `1.25` is immersed in water of refractive index `1.33`. Will the lens behave as a co

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
(a) Here, n=1.5, as per sign convention followed
`R_(1)=+20 cm and R_(2)=-20 cm`
`therefore` `1/f=(n-1)(1/R_(1)-1/R_(2))`
`=(1.5-1)[1/((+20))-1/((-20))]=0.5xx2/20=1/20`
`rArr f=+20 cm`
Incident ray travelling parallel to the axis of lens will converge at its second principal focus. Hence,
`L=+20cm`

4 views Answered 2023-02-05 15:29