The degree of ionization of HF in 1.00 m aqueous solution is (freezing = `1.86^(@)C`) is :
The degree of ionization of HF in 1.00 m aqueous solution is (freezing = `1.86^(@)C`) is :
A. 0.06
B. 0.12
C. 0.03
D. 0.09
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Correct Answer - a
`DeltaT_(f)=ixxK_(f)xxm`
`i=(DeltaT_(f))/(K_(f)xxm)=(0.197)/(1.86xx0.1)=1.059`
For dissociation
`alpha=((i-1))/((n-1))=((1.059-1))/((2-1))-0.059`
`=5.9%~~6%`
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