Light of wavelength 300 nm in medium A enters into medium B througha plane surface. If frequency of light is `5xx10^(14)` Hz and `v_(a)//v_(b)=4//5`,

Question

Light of wavelength 300 nm in medium A enters into medium B througha plane surface. If frequency of light is `5xx10^(14)` Hz and `v_(a)//v_(b)=4//5`,

Light of wavelength 300 nm in medium A enters into medium B througha plane surface. If frequency of light is `5xx10^(14)` Hz and `v_(a)//v_(b)=4//5`, then find absolute refractive indices of media A and B.

Monjur Alahi

7 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Speed `v_(A)=vlamda_(A)=5xx10^(14)xx300xx10^(-9)=1.5xx10^(8)`m/s
Absolute refractive index, `mu_(A)=c/(v_(A))=(3xx10^(8))/(1.5xx10^(8))=2`
We have, `muprop1/v`
`therefore (mu_(A)/mu_(B))=v_(B)/v_(A) rArr 2/mu_(B)=5/4`
Refracticvve index, `mu_(B)=0.8xx2=1.6`

7 views Answered 2023-02-05 15:29