A bar magnet when placed at an angle of `30^(@)` to the direction of magnetic field of `5xx10^(-2)`T, experiences a moment of couple `2.5xx10^(-6)`. I
A bar magnet when placed at an angle of `30^(@)` to the direction of magnetic field of `5xx10^(-2)`T, experiences a moment of couple `2.5xx10^(-6)`. If the length of the magnet is 5cm, then what will be its pole strength?
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Here , `theta=30^(@), B=5xx10^(-2)T`
`and " " tau=2.5xx10^(-6)N-m,`
`and " " 2l=5cm=0.05m,m=?`
`Rightarrow m=(tau)/(B(2l)sin theta)=(2.5xx20^(-6))/(5xx10^(-2)(0.05)sin30^(@))`
`therefore " " m=2xx10^(-3)A-m`
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