A solution containing 12.5 g of non-electrolyte substance in 175 g of water gave boiling point elevation of 0.70 K. Calculate the molar mass of th sub

Question

A solution containing 12.5 g of non-electrolyte substance in 175 g of water gave boiling point elevation of 0.70 K. Calculate the molar mass of th sub

A solution containing 12.5 g of non-electrolyte substance in 175 g of water gave boiling point elevation of 0.70 K. Calculate the molar mass of th substance (`K_(b)` for water=0.52 K kg `mol^(-1)`).

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - 53.06 g `mol^(-1)`
`M_(B)=(K_(b)xxW_(B))/(DeltaT_(b)xx W_(A))`
`W_(B)=12.5g , W_(A)=175.0g=0.175 kg, DeltaT_(b)=0.70 K`
`K_(b)=0.52" k kg mol"^(-1)`
`M_(B)=((12.5 g)xx(0.52" kg mol"^(-1)))/((0.70" K")xx(0.175" kg"))=53.06" g mol"^(-1)`.

4 views Answered 2023-02-05 15:29