An electron with speed v and a photon with speed c have the same de-Broglic wavelength. If the kinetic energy and momentum of electron is `E_(e)` and
An electron with speed v and a photon with speed c have the same de-Broglic wavelength. If the kinetic energy and momentum of electron is `E_(e)` and `P_(e)` and that of photon is `E_(ph)` and `P_(ph)` respectively, then correct statement is -
A. `(E_(e))/(E_(ph))=(2c)/(v)`
B. `(E_(e))/(E_(ph))=(v)/(2c)`
C. `(P_(e))/(P_(ph))=(2c)/(v)`
D. `(P_(e))/(P_(ph))=(v)/(2c)`
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Correct Answer - B
`(E_(e))/(E_(p))=((1)/(2)mv^(2))/(hupsilon)=(1)/(2)vxx(mv)/(h).(h)/(hupsilon)`
But `(h)/(mv)=(h)/(hupsilon)`
`:.(E_(e))/(E_(ph))=(1)/(2)v[(mv)/(h).(h)/(hupsilon).(c)/(c)]=(v)/(2c)`
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