Mole fraction of x M aqueous urea solution is : [Given : density of solution is `d gm//ml` ]
Mole fraction of x M aqueous urea solution is :
[Given : density of solution is `d gm//ml` ]
A. `(18x)/(1000d - 42 x)`
B. `(18 x)/(1000d - 60x)`
C. `(18x)/(1000d - 18x)`
D. None of these
5 views
1 Answers
Correct Answer - A
x moles of Urea in 1000 ml of solution
mass of solution = 1000 d gm
mass of solute `60 x gm`
mass of solvent `= (1000d - 60x) gm`
Mole fracction of urea `= (x)/(x + ((1000d - 60x)/(18)))`
`= (18x)/(18x + 1000d - 60x)`
`x_("urea") = (18x)/(1000d - 42x)`
5 views
Answered