The magnetic flux linked with a coil, in webers is given by the equation `phi=3t^(2)+4t+9`. Then, the magnitude of induced emf at t = 2 s

Question

The magnetic flux linked with a coil, in webers is given by the equation `phi=3t^(2)+4t+9`. Then, the magnitude of induced emf at t = 2 s

The magnetic flux linked with a coil, in webers is given by the equation `phi=3t^(2)+4t+9`. Then, the magnitude of induced emf at t = 2 s
A. 2 V
B. 4 V
C. 8 V
D. 16 V

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Magnitude of induced emf, `e=-(dphi)/(dt)`
`=-(d)/(dt)(3t^(2)+4t+9)=-(6t+4)`
`=-[6xx(2)+4]=-16`
`therefore" "|e|=16V`

4 views Answered 2023-02-05 15:29