For the reaction `N_(2)+2O_(2)to2NO_(2)` Given: at 1 atm , 300 K `{:(, S_(N_(2)) = 180 J//mol//K" ",C_(P)(N_(2))= 30 J//mol//K), (,S_(O_(2))= 220 J//m

Question

For the reaction `N_(2)+2O_(2)to2NO_(2)` Given: at 1 atm , 300 K `{:(, S_(N_(2)) = 180 J//mol//K" ",C_(P)(N_(2))= 30 J//mol//K), (,S_(O_(2))= 220 J//m

For the reaction
`N_(2)+2O_(2)to2NO_(2)`
Given: at 1 atm , 300 K
`{:(, S_(N_(2)) = 180 J//mol//K" ",C_(P)(N_(2))= 30 J//mol//K), (,S_(O_(2))= 220 J//mol//K" ",C_(P)(O_(2))= 30 J//mol//K),(,S_(NO_(2))= 240 J // mol //K" ",C_(P)(NO_(2)) = 40J//mol//K):}`
Calculate (i) `DeltaS_(300)K, 5 atm `
` " "(i) DeltaS_(400)K, 5 atm`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

(i)`(DeltaS_(r))_(300)= 2S_(NO_(2))- 2S_(O_(2)) - S_(N_(2)) = 2 xx 220 - 180 = - 140 J mol^(-1) K^(-1)`
`(DeltaCp)_(r) = 2C_(p)(NO_(2)) - 2C_(p)(O_(2))- C_(p)(N_(2)) = 2 xx 40- 2xx30-30= - 10 J mol^(-1)K^(-1)`
(ii)`(DeltaS_(r))_(400)= (DeltaS_(r))_(300) + (DeltaC_(p))_(r)ln.(T_(1))/(T_(2))= - 140 - 10 ln .(4)/(3) = - 142.88 mol^(-1)K^(-1)`