The standard enthalpy of formation of ammonia gas is Given: `N_(2)H_(4) (g) + H_(2) (g) rarr 2NH_(3) (g), Delta H_(r)^(@) = - 40 kJ//mol` `DeltaH_(f)^

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The standard enthalpy of formation of ammonia gas is Given: `N_(2)H_(4) (g) + H_(2) (g) rarr 2NH_(3) (g), Delta H_(r)^(@) = - 40 kJ//mol` `DeltaH_(f)^

The standard enthalpy of formation of ammonia gas is
Given: `N_(2)H_(4) (g) + H_(2) (g) rarr 2NH_(3) (g), Delta H_(r)^(@) = - 40 kJ//mol`
`DeltaH_(f)^(@) [N_(2)H_(4) (g)] = - 120 kJ//mol`
A. `-60`
B. `-180`
C. 40
D. `-80`

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`Delta_(r)H^(@)= sum_(i) a_(i) Delta_(f) H_("(products)")^(@)-sum_(i) b_(i) Delta_(f) H_("(reactants)")^(@)`
`-40=2Delta_(f) H^(@)+120`
`Delta_(f)H^(@)=-80`

4 views Answered 2023-02-05 15:29