An octahedral complex is prepared by mixing `CoCl_3` and `NH_3` in the molar ratio of 1 : 4 . 0.1 m solutioin of this complex was found to freeze at `

Question

An octahedral complex is prepared by mixing `CoCl_3` and `NH_3` in the molar ratio of 1 : 4 . 0.1 m solutioin of this complex was found to freeze at `

An octahedral complex is prepared by mixing `CoCl_3` and `NH_3` in the molar ratio of 1 : 4 . 0.1 m solutioin of this complex was found to freeze at `-0.372^(@) C`. What is the formula of the complex ? Given the molal depression content (`K_f)` for water = `1.86^(@)` cm

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Theoretical value of `deltaT_f` can be calculates as :
Observed value is twice the theoretical value, this means that each molecule of the complex dissociation is give two ions. This can be possible in case the complexes has the formula `[Co(NH_3)_(4)Cl_2]Cl` .

4 views Answered 2023-02-05 15:29