A swimmer coming out from a pool is covered with a film of water weighing about 18 g. calculte the internal energy of vaporisation at `100^(@)`, `[Del
A swimmer coming out from a pool is covered with a film of water weighing about 18 g. calculte the internal energy of vaporisation at `100^(@)`,
`[Delta_("vap")H^(@) for water at 373K = 40. 66 kJ mol^(-1)]`
A. `35.67 kJmol ^(-1)`
B. `35.67 kJmol ^(-1)`
C. `36.57kJmol ^(-1)`
D. `38.75kJmol ^(-1)`
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Correct Answer - b
we can repesent the process of evaporation as `18gH_(2)O(l)overset("veporistion")to 18 g H_(2)O(g)`
number of moles in ` 18 g H_(2)O(l)`
`(18g)/(18g mol^(-1))=1 mol`
`Delta_(vap)U=Delta_(vap)H^(-)-pDeltaV`
`Delta_(vap)H^(-)-Deltan_(g)RT`
assume steam behave as an ideal ga `Delta_(vap)U=(40.66)-(1)(8.314xx10^(-3))(373) `
40.66 - 3.10
` 37.56 KJ mol^(-1)`
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