if enthalpies of formatuon of `C_(2)H_(4)(g),CO_(2)(g) and H_(2)O(l)at 250^(@)and 1` atm pressure be 52 ,-394 and `-286 kJ mol ^(-1)` respectively,the

Question

if enthalpies of formatuon of `C_(2)H_(4)(g),CO_(2)(g) and H_(2)O(l)at 250^(@)and 1` atm pressure be 52 ,-394 and `-286 kJ mol ^(-1)` respectively,the

if enthalpies of formatuon of `C_(2)H_(4)(g),CO_(2)(g) and H_(2)O(l)at 250^(@)and 1` atm pressure be 52 ,-394 and `-286 kJ mol ^(-1)` respectively,the enthalpy of combustion of `C_(2) H_(4)(g)`will be
A. `1412 kJ mol ^(-1)`
B. `-1412 kJ mol ^(-1)`
C. `+ 141 .2 kJ mol ^(-1)`
D. ` -141 .2 kJ mol ^(-1)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - b
`C_(2)H_(4)+3O_(2)to 2CO_(2)+2H_(2)O`
`DeltaH("reaction")=[2xxDeltaH_(f)^(@)(CO_(2))+2xxDeltaH_(f)^(@)(H_(2)O)]`
`[DeltaH_(f)^(@)(C_(2)H_(4))+3xxDeltaH_(f)^(@)(O_(2))]`
`[2(-394)+2(286)]-[52+0]= 1412kJ mol^(-1)`

4 views Answered 2023-02-05 15:29