The titanium (atomic number 22) compound that does not exist is
A. TiO
B. `TiO_(2)`
C. `K_(2)TiF_(6)`
D. `TiCl_(3)`

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1 Answers

Correct Answer - C
`Ti(Z=22)` has configuration
`[Ar]^(18)3d^(2)4s^(2)` ltbr It can show oxidation states of +1,+2,+3,+4 In `K_(2)TiO_(4)` : oxidation state of Ti=+6 Therefore, it does not exist.

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