A compound of Xe and F is found to have 53.3% Xe (atomic weight = 133) Oxidation number of Xe in this compound is
A. `+2`
B. 0
C. `+4`
D. `+6`

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1 Answers

Correct Answer - D
`{:("Name of element","%age","At.mass","%Agr/At.mass","Simples ratio"),("Xe",53.3,133,(53.3)/(133)=0.398",",(0.398)/(0.398)=1),("F",46.7,19,(46.7)/(19)=2.45",",(2.45)/(0.398)=6):}`
`:.` Empirical formula `= XeF_(6)`
`:.` O.N. of Xe in `XeF_(6)=6`.

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