(i) An aqueous solution of a compound (A) is acidic towards litmus and (A) sublimes at about `300^(@)C`. (ii) (A) on treatment with an excess of `NH_(

Question

(i) An aqueous solution of a compound (A) is acidic towards litmus and (A) sublimes at about `300^(@)C`. (ii) (A) on treatment with an excess of `NH_(

(i) An aqueous solution of a compound (A) is acidic towards litmus and (A) sublimes at about `300^(@)C`.
(ii) (A) on treatment with an excess of `NH_(4)SCN` gives a red coloured compound (B) and on treatment with a solution of `K_(4)[Fe(CN)_(6)]` gives a blue coloured compound (C).
(iii) (A) on heating with excess of `K_(2)Cr_(2)O_(7)` in the presence of concentrated `H_(2)SO_(4)` evolves deep red vapours of (D).
(iv) On passing the vapour of (D) into a solution of NaOH and then adding the solution of acetic acid and lead acetate, a yellow precipitate of compound (E) is obtained.
Identify (A) to (E) and give chemical equations for the reactions.

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

The element belonging to Group 17 which sublimes is

2 Answers 4 Views

In what volume ratio should you mix `1.00 M` solution `NH_(4)Cl` and 1.00 M `NH_(3)` to produce a buffer solution of pH 9.80 ? `[pK_(b)(NH_(3))=4.74]`

2 Answers 4 Views

`Ag^(+)+hArr|Ag(NH_(3))_(2)|^(+), k_(1) = 6.8 xx 10^(-3)` `[Ag(NH_(3))]^(+) + NH_(3)hArr |Ag(NH_(3))_(2)|, k_(2) = 1.6xx10^(-3)` Then the formation co

2 Answers 4 Views

One mole of aqueous solution of the complex `CoCl_(3)5H_(2)O` when treated with excess of aqueous `AgNO_(3)` solution gave one mole of white pptof AgC

2 Answers 6 Views

`Ag^(+) + NH_(3) ltimplies [Ag(NH_(3))]^(+), k_(1)=6.8 xx 10^(-5)` `[Ag(NH_(3))]^(+) + NH_(3) ltimplies [Ag(NH_(3))_(2)]^(+)`, `k_(2) = 1.6xx10^(-3)`

2 Answers 8 Views

Calculate `DeltaG` for (i) `H_(2)O(l,2 atm , 300 K) to H_(2)O(g, 2 atm , 300 K ) ` (ii) `H_(2)O(l,P" "atm , 300 K) to H_(2)O(g, P" "atm , 300 K )` Cac

2 Answers 5 Views

What concentration of `OH^(-)` ions will reduce `NH_(4)^(+)` ion to `2xx10^(-5)M` in `0.4M` solution of `NH_(4)OH ? K(b)(NH_(4)OH)=1.8xx10^(-5)`

2 Answers 4 Views

An aqueous solution of colourless metal sulphate `M`, gives a white precipitate with `NH_(4)OH`.This was soluble in excess of `NH_(4)OH`. On passing `

2 Answers 4 Views

When a metal rod `M` is dipped into an aqueous colourless concentrated solution of compound `N` the solution turns light blue.Addition of aqueous `NaC

2 Answers 6 Views

(i)A black coloured compound `(B)` is formed on passing `H_(2)S` through the solution of a compound `(A)` in `NH_(4)OH` (ii)`(B)` on treatment with `H

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Since (A) with an excess of `NH_(4)SCN` gives a red coloured compound (B) onan on treatment with `K_(4)[Fe(CN)_(6)]` solution giveas a blue coloured compound, this means that the compound (A) contains `Fe^(3+)` ions ( may be `FeCl_(3)`). The reactions taking place in different steps are as follows :
(i) `underset((A))(FeCl_(3))+ underset("Amm. thiocyanate")(3NH_(4)SCN) to underset("(Red coloured)")underset("(B) Ferric thiocyanate")(Fe(SCN)_(3))+3NH_(4)Cl`
(ii) `underset((A))(4FeCl_(3))+ underset("Pot. ferrocyanide")(3K_(4)[Fe(CN)_(6)]) to underset("(Blue colured)")underset("(C) Ferric ferrocyanide")(Fe_(4)[Fe(CN)_(6)]_(3))+12KCl`
(iii) `underset((A))(2FeCl_(3))+ K_(2)Cr_(2)O_(7)+3H_(2)SO_(4) overset(Heat)to underset("(D) (Red vapours)")underset("Chromyl chloride")(2CrO_(2)Cl_(2))+Fe_(2)(SO_(4))_(3)+2KCl+3H_(2)O`
(iv) `CrO_(2)Cl_(2)+4NaOH to underset("Sod. chromate")(Na_(2)CrO_(4))+2NaCl+2H_(2)O`
`Na_(2)CrO_(4)+(CH_(3)COO)_(2)Pb to underset("(E) (Yellow ppt.)")underset("Lead chromate")(PbCrO_(4))+2CH_(3)COONa`