In the equation 2x^2 – hx + 2k = 0, the sum of the roots is 4 and the product of the roots is -3.
In the equation 2x2 – hx + 2k = 0, the sum of the roots is 4 and the product of the roots is -3. Then h and k have the values ………………… respectively.
A) 8 and -3
B) 8 and 6
C) 4 and -3
D) -3 and 8
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Correct option is (A) 8 and -3
Given equation is
\(2x^2-hx + 2k = 0\)
\(\therefore\) Sum of roots \(=\frac{-(-h)}2=\frac{h}2\)
\(\Rightarrow\frac h2=4\) \((\because\) Sum of roots = 4 (given))
\(\Rightarrow\) h = 8
And product of roots \(=\frac{2k}2=k\)
\(\Rightarrow\) k = -3 \((\because\) Product of roots = -3 (given))
Hence, h = 8 & k = -3
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