The values of ’k’ for which the equation 2x2 – kx + x + 8 = 0 will have real and equal roots are …………… 

A) 9 and -7 

B)-9 and 7 

C) only 9 

D) only -7

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2 Answers

Correct option is (A) 9 and -7

Given equation is

\(2x^2-kx+x+8=0\)

\(\Rightarrow\) \(2x^2+(1-k)x+8=0\)

For equal roots, we have

Discriminant = 0

\(\Rightarrow(1-k^2)-4\times2\times8=0\)

\(\Rightarrow(1-k^2)=64\)

\(\Rightarrow1-k=\pm8\)

\(\Rightarrow1-k=8\) \(or\;1-k=-8\)

\(\Rightarrow k=1-8=-7\) \(or\;k=1+8=9\)

Hence, the possible values of k are -7 & 9 for equal roots.

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Correct option is A) 9 and -7

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