For the chemical decomposition of `SO_(2)Cl_(2)`, its initial concentration is 0.842 mol `L^(-1)` and the concentration after two hours is `0.210 mol

Question

For the chemical decomposition of `SO_(2)Cl_(2)`, its initial concentration is 0.842 mol `L^(-1)` and the concentration after two hours is `0.210 mol

For the chemical decomposition of `SO_(2)Cl_(2)`, its initial concentration is 0.842 mol `L^(-1)` and the concentration after two hours is `0.210 mol L^(-1)`. What is the average rate of the reaction?

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

The reaction takes place in two steps as `(i) NO_(2) Cl _((g)) overset(K_(1)) to NO_(2(g)) +Cl_((g))` `(ii ) NO_(2) Cl_((g)) +Cl_((g)) overset(K_(2))

2 Answers 5 Views

Sulphuryl chloride, `SO_(2)Cl_(2)`, reacts with `H_(2)O` to give mixture of `H_(2)SO_(4)` and HCl. Aqueous solution of 1 mol `SO_(2)Cl_(2)` will be ne

2 Answers 10 Views

The rate of reaction, 2NO + `Cl_(2) to 2NOCl` is doubled when concentration of `Cl_(2)` is doubled and becomes eight times when concentration of both

2 Answers 4 Views

A reaction `SO_(2)Cl_(2) to SO_(2)+ Cl_(2)` is first order reaction with half life period `3.15 xx 10^(4)`s at `320^(@)`C. What percentage of `SO_(2)C

2 Answers 5 Views

The rate of reaction `2NO + Cl_(2) to 2NOCl` is doubled when the concentration of `Cl_(2)` is doubled and becomes eight times when the concentration o

2 Answers 8 Views

An organic compound undergoes first order decomposition. The time taken for the decomposition of `1//8` and `1//10` of its initial concentration are `

2 Answers 5 Views

The half-life of a radioisotope is 1.5 hours. If its initial mass is 32g, the mass left undecayed after 6 hours is

2 Answers 9 Views

The half-life of a radioactive isotope is three hours. If the initial mass of the isotope were 256 g, the undecayed remaining mass after 18 hours woul

2 Answers 4 Views

The half-life of a radioisotope is four hours. If the initial mass of the isotope was 200 g , the undecayed mass remaining after 24 hours is :

2 Answers 4 Views

`SO_(3) (g)` is produced as : `SO_(2) (g) + (1)/(2) O_(2) (g) hArr SO_(3) (g)` At `900 K, 0.2 `mol of `SO_(2)` and 0.4 mol of `O_(2)` are taken in 2L

2 Answers 10 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

`Delta[SO_(2)Cl_(2)]=(0.210-0.842) = -0.632 mol L^(-1), Deltat=2` hours.
Average rate of reaction = `(-[SO_(2)Cl_(2)])/(Deltat) = -(0.632 mol L^(-1))/(2hr) = 0.316 mol L^(-1)hr^(-1)`.

4 views Answered 2023-02-05 15:29