One mole of a symmetrical alkene on hydrolyses gives two moles of an aldehyde having a molecular mas of 44 u. The alkene is
A. 2-butene
B. ethene
C. propene
D. 1-butene.

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Correct Answer - A
The aldehyde with molecular mass will 44u is `CH_(3)CHO` (acetaldehyde) `therefore` symmetrical alkene is 2-butane
`underset("2-butene")(CH_(3)CH=CHCH_(3))overset((i)O_(3))underset((ii)Zn//H_(2)O)rarrundersetunderset("Mol. mass=44")("Acetaldehyde")(2CH_(3)CHO)`

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