For the reaction A + B `to` products, rate low expression for rate =`k[A][B]^(2)`. If the volume of the vessel is reduced to `1/3` of its original vol

Question

For the reaction A + B `to` products, rate low expression for rate =`k[A][B]^(2)`. If the volume of the vessel is reduced to `1/3` of its original vol

For the reaction A + B `to` products, rate low expression for rate =`k[A][B]^(2)`. If the volume of the vessel is reduced to `1/3` of its original volume then what will be the effect on the rate of reaction?

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

rate = `k[A][B]^(2)`
By reducing the volume to `1/3` of its original volume, the concentration of the reactants will become three times.
`therefore` rate = `k[3A][3B]^(2)=27k[A][B]^(2)` ltbr. Hence, the reaction rate will become 27 times its initial rate.

5 views Answered 2023-02-05 15:29