For the reaction `NO_(2)(g) + CO(g) to NO(g) + CO_(2)(g)`, the experimentally determined rate expression at 40 K is: rate =`k[NO_(2)]^(2)` What is the

Question

For the reaction `NO_(2)(g) + CO(g) to NO(g) + CO_(2)(g)`, the experimentally determined rate expression at 40 K is: rate =`k[NO_(2)]^(2)` What is the

For the reaction `NO_(2)(g) + CO(g) to NO(g) + CO_(2)(g)`, the experimentally determined rate expression at 40 K is:
rate =`k[NO_(2)]^(2)`
What is the proposed mechanism for the reaction?

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

According to available information, rate is proportional to the square of the molar concentration of `NO_(2)`. Therefore, the proposed mechanism for the reaction is:
`NO_(2) +NO_(2) overset(Slow)toNO+NO_(3)`
`NO_(3) + CO overset("Fast")to CO_(2) + NO_(2)`

5 views Answered 2023-02-05 15:29