The emf of a galvanic cell constituted with the electrodes `Zn^(2+)//Zn(E^(@)=-0.76" V")` and `Fe^(2+)//Fe(E^(@)=-0.41" V")` is :
The emf of a galvanic cell constituted with the electrodes `Zn^(2+)//Zn(E^(@)=-0.76" V")` and `Fe^(2+)//Fe(E^(@)=-0.41" V")` is :
A. `-0.35" V"`
B. `+1.17" V"`
C. `+0.35" V"`
D. `-1.17" V"`
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Correct Answer - C
(c ) `E_(cell)^(@)=E_(cathode)^(@)-E_(anode)^(@)`
`=(-0.41)-(-0.76)=0.35" V"`
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