A galvanic cell consists of a metallic zinc plate immersed in 0.1 M `Zn (NO_(3))_(2)` solution and metallic plate of lead in 0.02M `Pb(NO_(3))_(2)` so

Question

A galvanic cell consists of a metallic zinc plate immersed in 0.1 M `Zn (NO_(3))_(2)` solution and metallic plate of lead in 0.02M `Pb(NO_(3))_(2)` so

A galvanic cell consists of a metallic zinc plate immersed in 0.1 M `Zn (NO_(3))_(2)` solution and metallic plate of lead in 0.02M `Pb(NO_(3))_(2)` solution. Calculate the emf of the cell.
Write the chemical equation for the electrode reactions and represent the cell.
`("Given" : E^(@) Zn^(2+)ZN=0.76V, " " E^(@)Pb^(2+)//Pb = -0.13V)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

The reaction takes place in two steps as `(i) NO_(2) Cl _((g)) overset(K_(1)) to NO_(2(g)) +Cl_((g))` `(ii ) NO_(2) Cl_((g)) +Cl_((g)) overset(K_(2))

2 Answers 5 Views

The cathode in a galvanic cell and electrolytic cell is

2 Answers 4 Views

In a simple Galvanic cell , which is in standard state , half cell reactions with their appropriate oxidation potentials are `{:(Pb (s) - 2e^(-) to Pb

2 Answers 8 Views

If in a galvanic cell, the cell reaction is reversed as `Cu(s)|Cu^(2_(aq)||Zn^(2)aq|Zn` the cell potential will be

2 Answers 5 Views

A current is passed through two cells connected in series. The first cell contain `x(NO_(3))_(2)` (aq) and the second cell contains `y(NO_(3))_(2)(aq)

2 Answers 4 Views

What is the relationship between Gibbs free energy of the cell reaction in a galvanic cell and the emf of the cell ? When will the maximum work be obt

2 Answers 4 Views

A galvanic cell has `E_(cell)^(@)=1.5" V"`. If an opposing potential of `1.5" V"` is applied to cell, what will happen to the cell reaction and curren

2 Answers 5 Views

For a reaction carried at 400 K, `NO_(2)(g) + CO_(2)(g) to CO_(2)(g) + NO_(2)(g)`, the proposed mechanism is as follows: `NO_(2) + NO_(2) overset("Slo

2 Answers 4 Views

For the reaction: `2NO_(2)(g) + F_(2)(g) to NO_(2)F +F` (slow) ii) `NO_(2) + F to NO_(2)F + F` (fast) What is the predicted rate law?

2 Answers 7 Views

For a solution obtained by mixing equal volumes of `0.02M KOH` solution `&0.2MB` (weak diacidic base),` K_(b_(1))=10^(-7) & K_(b_(2))=10^(-14))` solut

2 Answers 16 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - 0.61`" V "`
Cell reaction : `Zn(s)+Pb^(2+)(0.02M)to Zn^(2+)(0.1" M")+Pb(s)`
`E_(cell)=E_(cell)^(@)-(0.0591)/(2)"log"([Zn^(2+)])/([Pb^(2+)])=[-0.13-(0.76)]-(0.0591)/(2)"log"(0.1)/(0.02)`
`=0.63-0.02955" log "5=0.63-0.02955xx0.69877`
`=0.63-0.02065=0.609345" V "=0.61" V "`.

4 views Answered 2023-02-05 15:29