When 32.25 g of ethyl chloride is subjected to dehydrohalogenation reaction, the yield of alkene formed is 50%. The mass of the product formed is (atomic mass of Cl = 35.5)
A. 14 g
B. 28 g
C. `66.5 g`
D. 7 g

5 views

1 Answers

Correct Answer - D
`underset(64.5g)(CH_(3)CH_(2)Cl)overset(KOH(alc.)Delta)underset(-KCl, -H_(2)O)rarrunderset(28 g)(CH_(2)=CH_(2))`
yield of `CH_(2)=CH_(2)=(28)/(64.5)xx(32.25xx56)/(100)=7 g`

5 views

Related Questions