Consider the following reaction `RONa+H_(2)C to ROH+NaOH` `ROH+NaNH_(2) to RONa+NH_(3)` Predict which of the following order reagarding base strength

Question

Consider the following reaction `RONa+H_(2)C to ROH+NaOH` `ROH+NaNH_(2) to RONa+NH_(3)` Predict which of the following order reagarding base strength

Consider the following reaction
`RONa+H_(2)C to ROH+NaOH`
`ROH+NaNH_(2) to RONa+NH_(3)`
Predict which of the following order reagarding base strength is correct.
A. `OH^(-)lt NH_(2)^(-) lt RO^(-)`
B. `NH_(2)^(-)lt OH^(-) lt RO^(-)
C. `OH^(-)lt RO^(-) lt NH_(2)^(-)
D. `RO^(-)lt NH_(2)^(-) lt OH^(-)

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - C
`R-overset(-)(Ona^(+)) +H_(2)O to ROH+NaOH`
`ROH+NaNH_(2) to RONa+NH_(3)`
Since the reaction is favoured in forward direction, `RO^(-)` is stronger base than `OH^(-)`. According to the second reaction `NH_(2)^(-)` is stronger than `RO^(-) as NH_(2)^(-) "forms" NH_(3)`. The order of basic strength if `OH^(-) lt RO^(-) lt NH_(2)^(-)` .