If values of `Lambda_(0)` of `NH_(4)Cl , NaOH and NaCl` are 130 , 127 and `109 Omega^(-1) cm^(2) eq^(-1)` respectively . The `Lambda_(NH_(4)OH)^(@)` i

Question

If values of `Lambda_(0)` of `NH_(4)Cl , NaOH and NaCl` are 130 , 127 and `109 Omega^(-1) cm^(2) eq^(-1)` respectively . The `Lambda_(NH_(4)OH)^(@)` i

If values of `Lambda_(0)` of `NH_(4)Cl , NaOH and NaCl` are 130 , 127 and `109 Omega^(-1) cm^(2) eq^(-1)` respectively . The `Lambda_(NH_(4)OH)^(@)` in `Omega^(-1) cm^(2) eq^(-1)` is
A. 456
B. 238
C. 196
D. 22

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`Lambda_(NH_(4)OH)^(@)= Lambda_(NH_(4)Cl)^(@) + Lambda_(NaOH)^(@) - Lambda_(NaCl)^(@)`
`= 130 + 217 - 109`
`= +238 Omega cm^(2) eq^(-1)`

4 views Answered 2023-02-05 15:29