If the perimeter of a rectangular room is 34 and the length of the diagonal is 13, then the dimensions of the room are …………
If the perimeter of a rectangular room is 34 and the length of the diagonal is 13, then the dimensions of the room are …………
A) 7, 6
B) 11, 6
C) 12, 5
D) 12, 6
2 Answers
Correct option is (C) 12, 5
Let length & breadth of the rectangular room are \(l\;and\;b\) respectively.
\(\because\) Perimeter of a rectangular room is 34.
i.e., \(2(l+b)\) = 34
\(\Rightarrow\) \(l+b=\frac{34}2\) = 17
\(\Rightarrow\) \(l+b=17\) _________(1)
\(\because\) Length of the diagonal is 13.
\(\therefore\) \(\sqrt{l^2+b^2}=13\)
\(\Rightarrow\) \(l^2+b^2=13^2\)
\(\Rightarrow\) \(l^2+b^2=169\) _________(2)
\(\because\) \((l+b)^2=l^2+b^2+2lb\)
\(\Rightarrow\) \(17^2=169+2lb\) (From (1) and (2))
\(\Rightarrow\) \(2lb=17^2-169\)
= 289 - 169
\(\Rightarrow\) \(2lb=120\) _________(3)
\(\therefore\) \((l-b)^2=l^2+b^2-2lb\)
= 169 - 120 (From (3))
= 49 \(=7^2\)
\(\Rightarrow\) \(l-b=7\) _________(4)
By adding (1) & (4), we get
\(2l\) = 17+7 = 24
\(\Rightarrow l=\frac{24}2=12\)
\(\therefore\) b = 17+b
\(\Rightarrow\) b = 17 - 12 = 5
Hence, the dimensions of the room are \(l=12\) & b = 5.