A complex `PtCl_(4).5NH_(3)` shows a molar conductance of 402 `ohm^(-1)cm^(2) mol^(-1)` in water and precipitate three mole of AgCl with `AgNO_(3)` .

Question

A complex `PtCl_(4).5NH_(3)` shows a molar conductance of 402 `ohm^(-1)cm^(2) mol^(-1)` in water and precipitate three mole of AgCl with `AgNO_(3)` .

A complex `PtCl_(4).5NH_(3)` shows a molar conductance of 402 `ohm^(-1)cm^(2) mol^(-1)` in water and precipitate three mole of AgCl with `AgNO_(3)` . The formula of the complex is
A. `[Pt(NH_(3))_(6)Cl_(4)`
B. `[Pt(NH_(3))_(5)Cl]Cl_(3)`
C. `[Pt(NH_(3))_(4)Cl_(2)]Cl_(2)`
D. `[Pt(NH_(3))_(3)Cl_(3)]Cl`.

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Molar conductance of 402 `ohm^(-1) cm^(2) mol^(-1)` indicate four ions so the formula is `[Pt(NH_(3))_(5)Cl]Cl_(3)` i.e., three `Cl^(-)` ions can be precipitated.

5 views Answered 2023-02-05 15:29