If equivalent conductance of 1 M benzoic acid is 12.8 `ohm^(-1) cm^(2)` and if the conductance of benzoic ion and `H^(+)` ion are 42 and 288.42 `ohm^(

Question

If equivalent conductance of 1 M benzoic acid is 12.8 `ohm^(-1) cm^(2)` and if the conductance of benzoic ion and `H^(+)` ion are 42 and 288.42 `ohm^(

If equivalent conductance of 1 M benzoic acid is 12.8 `ohm^(-1) cm^(2)` and if the conductance of benzoic ion and `H^(+)` ion are 42 and 288.42 `ohm^(-1)` respectively, its degree of dissociation is
A. 0.39
B. 0.039
C. 0.0035
D. 0.00039

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`(^^_(C_(6)H_(5)COOH)^(@))=lambda_(C_(6)H_(5)COO^(-))^(@)+lambda_(H^(+))^(@)`
`=42+288.42=330.42`
`alpha=(^^_( m)^(@))/(^^_( m)^(@))=(1 2.8)/(330.42)= 0.03 9=3.0%`

5 views Answered 2023-02-05 15:29