An element X has the following isotopic composition `.^(200)X : 90%, .^(199)X: 8.0%, .^(202)X:2%` . The Weighed average atomic mass of naturally occur

Question

An element X has the following isotopic composition `.^(200)X : 90%, .^(199)X: 8.0%, .^(202)X:2%` . The Weighed average atomic mass of naturally occur

An element X has the following isotopic composition `.^(200)X : 90%, .^(199)X: 8.0%, .^(202)X:2%` . The Weighed average atomic mass of naturally occurring element X is closet to
A. 199 a.m.u.
B. 200 a.m.u.
C. 201 a.m.u.
D. 202 a.m.u.

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
Average atomic mass, `overset(-)(A)=Sigmaf_(i)A_(i)`
(`f_(i)`=fractional abundance, `A_(i)`=atomic mass)
Atomic mass
`=0.90xx200+0.08xx199+0.02xx202`
`=180+15.92+4.04~~200`

6 views Answered 2023-02-05 15:29