If 0.5 mol of `BaCl_(2)` is mixed with 0.2 mol of `Na_(3)PO_(4)`, the maximum number of moles of `Ba_(3)(PO_(4))_(2)` that can be formed is
If 0.5 mol of `BaCl_(2)` is mixed with 0.2 mol of `Na_(3)PO_(4)`, the maximum number of moles of `Ba_(3)(PO_(4))_(2)` that can be formed is
A. `0.7`
B. `0.5`
C. `0.1`
D. `0.2`
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Correct Answer - C
`underset(3mol)(3BaCl_(2))+underset(2mol)(2Na_(3)PO_(4))tounderset(1mol)(Ba_(3)(PO_(4))_(2))+6NaCl`
Here `NaPO_(4)` gives 1 mol of `Ba_(3)(PO_(4))_(2)` 0.2 mol of `Na_(3)PO_(4)` will give 0.1 mol of `Ba_(3)(PO_(4))_(2)`
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