NO reacts with `O_(2)` to form `NO_(2)`. When 10 g of `NO_(2)` is formed during the reaction, the mass of `O_(2)` consumed is

Question

NO reacts with `O_(2)` to form `NO_(2)`. When 10 g of `NO_(2)` is formed during the reaction, the mass of `O_(2)` consumed is

NO reacts with `O_(2)` to form `NO_(2)`. When 10 g of `NO_(2)` is formed during the reaction, the mass of `O_(2)` consumed is
A. `1*90 g`
B. `5*0 g`
C. `3*48 g`
D. `13*9 g`

Monjur Alahi

8 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`2NO+underset(32g)(O_(2))tounderset(2xx46g)(2NO_(2))`
`92 g NO_(2)` uses `O_(2) = 32g`
`:. 10 g NO_(2)` uses `O_(2) = (32)/(92)xx10=3*48g`

8 views Answered 2023-02-05 15:29