What is the value of `Delta H` for a reversible isothermal evaporation of 180g of water at `100^(@)C` ? Latent ehat of evaporation of water `=539.7 ca

Question

What is the value of `Delta H` for a reversible isothermal evaporation of 180g of water at `100^(@)C` ? Latent ehat of evaporation of water `=539.7 ca

What is the value of `Delta H` for a reversible isothermal evaporation of 180g of water at `100^(@)C` ? Latent ehat of evaporation of water `=539.7 cal K^(-1)g^(-1)` ?
A. 5.397kcal
B. 97.146 kcal
C. `(539.7 xx 373)/(1000)kcal`
D. `(10xx373xx539.7)/(1000)kcal`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`Delta H` is the heat absorbed at constant pressure. Thus during evaporation (of 180g) of water as the process is done at constant pressure.
`:. Delta H=180 xx 539.7 =97146cal` or `97.146 kcal`

4 views Answered 2023-02-05 15:29