A weak acid of dissociation constant `10^(-5)` is being titrated with aqueous NaOH solution . The pH at the point of one third of neutralization of th

Question

A weak acid of dissociation constant `10^(-5)` is being titrated with aqueous NaOH solution . The pH at the point of one third of neutralization of th

A weak acid of dissociation constant `10^(-5)` is being titrated with aqueous NaOH solution . The pH at the point of one third of neutralization of the acid will be
A. `5 + log - log 3`
B. `5- log 2`
C. `5- log 3`
D. `5- log 6`

Monjur Alahi

7 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - B
On partial neutralization of weak acid, salt is formed. Hence it becomes buffer
`:. pH =pK_(a)+log. (|"Salt"|)/(|"Acid"|).`
`1//3` rd neutralization of the acid means out of 1 mole of the acid, salt formed is `= 1//3 ` mole of acid left `=2//3` mole
`:. pH =-log (10^(-5))+log.(1//3)/(2//3)`
`=5+log.(1)/(2)=5-log 2`