If `K_(a)` of `HCN =4xx10^(-10)` , then the pH of `2.4 xx 10^(-1)` molar HCN(aq) is
A. `2x10^(-5)`
B. 4.7
C. `2.0`
D. `5.0`

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1 Answers

Correct Answer - D
`[H_(3)O^(+)]=sqrt(K_(a)xxC)`
`=(4xx10^(-10)xx2.5 xx 10^(-1))^(1//2)`
`=(10^(10))^(1//2)=10^(-5)M`
`:. pH =5`

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