A particular reaction has a negative value for the free energy change. Then at ordinary temperature

A particular reaction has a negative value for the free energy change. Then at ordinary temperature
A. It has a large `-ve` value for the entropy change
B. It has a large `+ve` value for the entropy change
C. It has small `+ve` value for enthalpy change
D. It has a `+ve` value for the entropy change and a `-ve` value for the enthalpy change

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - D
The reaction is spontaneous `(DeltaG=-ve)`. Thus, at ordinary temperature
`DeltaS=+ve`, `DeltaH=-ve`.

4 views Answered 2023-02-05 15:29

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